Codeforces 837E Vasya's Function

题目链接:http://codeforces.com/contest/837/problem/E

题意:略。

思路:题解报告看这里

#pragma comment(linker, "/STACK:102400000,102400000")
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <cmath>
#include <string>
#include <vector>
#include <cstdio>
#include <cctype>
#include <cstring>
#include <sstream>
#include <cstdlib>
#include <iostream>
#include <algorithm>
#define MOD 1e9+7
#define lson root<<1,l,mid
#define rson root<<1|1,mid+1,r
#define Key_Value ch[ch[root][1]][0]
#define DBN1(a)           cerr<<#a<<"="<<(a)<<"\n"
#define DBN2(a,b)         cerr<<#a<<"="<<(a)<<", "<<#b<<"="<<(b)<<"\n"
#define DBN3(a,b,c)       cerr<<#a<<"="<<(a)<<", "<<#b<<"="<<(b)<<", "<<#c<<"="<<(c)<<"\n"
#define DBN4(a,b,c,d)     cerr<<#a<<"="<<(a)<<", "<<#b<<"="<<(b)<<", "<<#c<<"="<<(c)<<", "<<#d<<"="<<(d)<<"\n"
#define DBN5(a,b,c,d,e)   cerr<<#a<<"="<<(a)<<", "<<#b<<"="<<(b)<<", "<<#c<<"="<<(c)<<", "<<#d<<"="<<(d)<<", "<<#e<<"="<<(e)<<"\n"
#define DBN6(a,b,c,d,e,f) cerr<<#a<<"="<<(a)<<", "<<#b<<"="<<(b)<<", "<<#c<<"="<<(c)<<", "<<#d<<"="<<(d)<<", "<<#e<<"="<<(e)<<", "<<#f<<"="<<(f)<<"\n"
#define clr(a,x) memset(a,x,sizeof(a))
using namespace std;
typedef long long ll;
const int maxn=500000+5;
const int INF=0x3f3f3f3f;
const double PI=acos(-1.0);
template<typename T> inline T gcd(T&a,T&b){return b==0?a:gcd(b,a%b);}
template<typename T> inline T lcm(T&a,T&b){return a/gcd(a,b)*b;}
template<typename T>
inline T read(T&x){
    x=0;int _f=0;char ch=getchar();
    while(ch<'0'||ch>'9')_f|=(ch=='-'),ch=getchar();
    while(ch>='0'&&ch<='9')x=x*10+ch-'0',ch=getchar();
    return x=_f?-x:x;
}
ll x,y;
vector<ll>vec;
int main(){
    read(x),read(y);
    ll g=__gcd(x,y);
    x/=g,y/=g;
    for (ll i=2;i*i<=x;i++){
        while (x%i==0){
            x/=i;
            vec.push_back(i);
        }
    }
    if (x>1) vec.push_back(x);
    ll ans=0;
    while (y){
        ll tmp=y;
        for (int i=0;i<(int)vec.size();i++){
            tmp=min(tmp,y%vec[i]);
        }
        ans+=tmp;
        y-=tmp;
        vector<ll>t;
        for (int i=0;i<(int)vec.size();i++){
            if (y%vec[i]==0){
                y/=vec[i];
            }
            else t.push_back(vec[i]);
        }
        vec.swap(t);
    }
    printf("%lld\n",ans);
    return 0;
}

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